check the user like of the like button and display something immediately in facebook app, 謝謝

edited 四月 2014 in 進階PHP討論
I have a question which I have tested many times.
How I can check the user like of the like button and display something immediately?

<? ob_start(); ?>
header("Content-Type:text/html; charset=utf-8");
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "">;
<html xmlns="">;
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<meta http-equiv="content-language" content="zh-hk">
<title>My Travel Package</title>
<div id="fb-root"></div>
window.fbAsyncInit = function() {
appId : '611082462236661',
status : true,
xfbml : true
(function(d, s, id){
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) {return;}
js = d.createElement(s); = id;
js.src = "//";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));
require 'src/facebook.php';
$app_id = "611082462236661";
$app_secret = "ae07bc7c7da48c5f432fce167297e918";
$facebook = new Facebook(array(
'appId' => $app_id,
'secret' => $app_secret,
'cookie' => true
$signed_request = $facebook->getSignedRequest();
$liked = $signed_request[page][liked];
if ($liked==1) {
echo'<img src="fb.jpg"/>';
echo'<div class="fb-share-button" data-href=""; data-type="button_count"></div>';
} else {
echo'Please like us!';
echo'<div class="fb-like" data-href=""; data-layout="button_count" data-action="like" data-show-faces="false" data-share="false"></div>';

Hope you can help me. Thanks.


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