check the user like of the like button and display something immediately in facebook app, 謝謝

edited 四月 2014 in 進階PHP討論
HI EVERYONE,
I have a question which I have tested many times.
How I can check the user like of the like button and display something immediately?
https://www.facebook.com/keung725/app_611082462236661
http://mycoupon.com.hk/1/



<? ob_start(); ?>
<?php
header(\"Content-Type:text/html; charset=utf-8\");
?>
<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\">
<html xmlns=\"http://www.w3.org/1999/xhtml\">
<head>
<meta http-equiv=\"content-type\" content=\"text/html; charset=utf-8\">
<meta http-equiv=\"content-language\" content=\"zh-hk\">
<title>My Travel Package</title>
</head>
<div id=\"fb-root\"></div>
<script>
window.fbAsyncInit = function() {
FB.init({
appId : '611082462236661',
status : true,
xfbml : true
});
};
(function(d, s, id){
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) {return;}
js = d.createElement(s); js.id = id;
js.src = \"//connect.facebook.net/zh_HK/all.js\";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));
</script>
<body>
<?php
mb_internal_encoding('UTF-8');
require 'src/facebook.php';
$app_id = \"611082462236661\";
$app_secret = \"ae07bc7c7da48c5f432fce167297e918\";
$facebook = new Facebook(array(
'appId' => $app_id,
'secret' => $app_secret,
'cookie' => true
));
$signed_request = $facebook->getSignedRequest();
$liked = $signed_request[page][liked];
if ($liked==1) {
echo'<img src=\"fb.jpg\"/>';
echo'<div class=\"fb-share-button\" data-href=\"https://www.facebook.com/keung725\" data-type=\"button_count\"></div>';
} else {
echo'Please like us!';
echo'<div class=\"fb-like\" data-href=\"https://www.facebook.com/keung725\" data-layout=\"button_count\" data-action=\"like\" data-show-faces=\"false\" data-share=\"false\"></div>';
}
?>
</body>
</html>



Hope you can help me. Thanks.
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